Laws of Exponents
Exponents are also called Powers or Indices
The exponent of a number says how many times to use the number in a multiplication.
In this example: 8^{2} = 8 × 8 = 64

Try it yourself: 
So an Exponent just saves you writing out lots of multiplies!
Example: a^{7}
a^{7} = a × a × a × a × a × a × a = aaaaaaa
Example: x^{6} = xxxxxx
The Key to the Laws
Writing all the letters down is the key to understanding the Laws
Example: x^{2}x^{3} = (xx)(xxx) = xxxxx = x^{5}
Which shows that x^{2}x^{3} = x^{5}, but more on that later!All you need to know ...
The "Laws of Exponents" (also called "Rules of Exponents") come from three ideas:The exponent says how many times to use the number in a multiplication.  
A negative exponent means divide, because the opposite of multiplying is dividing  

If you understand those, then you understand exponents!
And all the laws below are based on those ideas.
Laws of Exponents
Here are the Laws (explanations follow):Law  Example 

x^{1} = x  6^{1} = 6 
x^{0} = 1  7^{0} = 1 
x^{1} = 1/x  4^{1} = 1/4 
x^{m}x^{n} = x^{m+n}  x^{2}x^{3} = x^{2+3} = x^{5} 
x^{m}/x^{n} = x^{mn}  x^{6}/x^{2} = x^{62} = x^{4} 
(x^{m})^{n} = x^{mn}  (x^{2})^{3} = x^{2×3} = x^{6} 
(xy)^{n} = x^{n}y^{n}  (xy)^{3} = x^{3}y^{3} 
(x/y)^{n} = x^{n}/y^{n}  (x/y)^{2} = x^{2} / y^{2} 
x^{n} = 1/x^{n}  x^{3} = 1/x^{3} 
And the law about Fractional Exponents:  
Laws Explained
The first three laws above (x^{1} = x, x^{0} = 1 and x^{1} = 1/x) are just part of the natural sequence of exponents. Have a look at this:Example: Powers of 5  

.. etc..  
5^{2}  1 × 5 × 5  25  
5^{1}  1 × 5  5  
5^{0}  1  1  
5^{1}  1 ÷ 5  0.2  
5^{2}  1 ÷ 5 ÷ 5  0.04  
.. etc.. 
The law that x^{m}x^{n} = x^{m+n}
With x^{m}x^{n}, how many times will you end up multiplying "x"? Answer: first "m" times, then by another "n" times, for a total of "m+n" times.
Example: x^{2}x^{3} = (xx)(xxx) = xxxxx = x^{5}
So, x^{2}x^{3} = x^{(2+3)} = x^{5}
The law that x^{m}/x^{n} = x^{mn}
Like the previous example, how many times will you end up multiplying "x"? Answer: "m" times, then reduce that by "n" times (because you are dividing), for a total of "mn" times.
Example: x^{4}/x^{2} = (xxxx) / (xx) = xx = x^{2}
So, x^{4}/x^{2} = x^{(42)} = x^{2}
(Remember that x/x = 1, so every time you see an x "above the line" and one "below the line" you can cancel them out.)
This law can also show you why x^{0}=1 :Example: x^{2}/x^{2} = x^{22} = x^{0} =1
The law that (x^{m})^{n} = x^{mn}
First you multiply "m" times. Then you have to do that "n" times, for a total of m×n times.
Example: (x^{3})^{4} = (xxx)^{4} = (xxx)(xxx)(xxx)(xxx) = xxxxxxxxxxxx = x^{12}
So (x^{3})^{4} = x^{3×4} = x^{12}
The law that (xy)^{n} = x^{n}y^{n}
To show how this one works, just think of rearranging all the "x"s and "y" as in this example:
Example: (xy)^{3} = (xy)(xy)(xy) = xyxyxy = xxxyyy = (xxx)(yyy) = x^{3}y^{3}
The law that (x/y)^{n} = x^{n}/y^{n}
Similar to the previous example, just rearrange the "x"s and "y"s
Example: (x/y)^{3} = (x/y)(x/y)(x/y) = (xxx)/(yyy) = x^{3}/y^{3}
The law that
OK, this one is a little more complicated!
I suggest you read Fractional Exponents first, or this may not make sense.
Anyway, the important idea is that:
x^{1/n} = The nth Root of x
And so a fractional exponent like 4^{3/2} is really saying to do a cube (3) and a square root (1/2), in any order.
Just remember from fractions that m/n = m × (1/n):
Example:
The order does not matter, so it also works for m/n = (1/n) × m:
Example:
And That Is It!
If you find it hard to remember all these rules, then remember this:
you can work them out when you understand the
three ideas at the top of this page
three ideas at the top of this page
Oh, One More Thing ... What if x= 0?
Positive Exponent (n>0)  0^{n} = 0  
Negative Exponent (n<0)  Undefined! (Because dividing by 0 is undefined)  
Exponent = 0  Ummm ... see below! 
The Strange Case of 0^{0}
There are two different arguments for the correct value of 0^{0}.0^{0} could be 1, or possibly 0, so some people say it is really "indeterminate":
x^{0} = 1, so ...  0^{0} = 1  
0^{n} = 0, so ...  0^{0} = 0  
When in doubt ...  0^{0} = "indeterminate" 